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(C) The maximum height attained by the rocket corresponds to the area under the velocity-time $(v-t)$ graph until the velocity becomes zero.From the g

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$55$

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(C) The maximum height attained by the rocket corresponds to the area under the velocity-time $(v-t)$ graph until the velocity becomes zero.From the graph,the velocity is positive from $t = 0$ to $t = 110 \ s$.The area under the $v-t$ graph is a triangle with base $b = 110 \ s$ and height $h = 1000 \ m/s$.Maximum height $= 	ext{Area of triangle} = \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height}$Maximum height $= \frac{1}{2} 	imes 110 \ s 	imes 1000 \ m/s$Maximum height $= 55 	imes 1000 \ m = 55000 \ m$Since $1 \ km = 1000 \ m$,we have:Maximum height $= 55 \ km$.

The graph shows the variation of velocity of a rocket with time. The maximum height attained by the rocket is ........... $km$ :-

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